Resources

Mike Boyd Video
Numberphile Video

Formula

  • is the day in number form
    • Sunday = 0 (Noneday)
    • Monday = 1 (Oneday
    • Tuesday = 2 (Twosday)
    • Wednesday = 3 (Triday)
    • Thursday = 4 (Foursday)
    • Friday = 5 (Fiveday)
    • Saturday = 6 (Sixday)
  • is the year
  • removes the last two digits of . For example, is 19

f(x)=
\begin{cases}
0 & x\equiv 1~\left(\text{mod }4\right) \
5 & x\equiv 2~\left(\text{mod }4\right) \
3 & x\equiv 3~\left(\text{mod }4\right) \
2 & x\equiv 0~\left(\text{mod }4\right)
\end{cases}

* $\displaystyle \text{mod}\left(Y,100\right)$ takes the last two digits of $\displaystyle Y$. For example, $\displaystyle \text{mod}\left(1984,100\right)=84$ * $\displaystyle g(x)\equiv {\left\lfloor \frac{x}{4}\right\rfloor}+x$ * Can simplify using Conway's method of subdividing years by 12 (see additional notes) * $\displaystyle D$ is the date number * $\displaystyle D_{D}$ is the Doomsday number for the particular month * For months 1 (January), 2 (February), ..., and etc., $\displaystyle D_{D}$ is as follows: 1. 3 (4 for leap years) 2. 28 (29 for leap years) 3. 14 ($\displaystyle \pi$-day) 4. 4 5. 9 6. 6 7. 11 8. 8 9. 5 10. 10 11. 7 12. 12 * E.g: What day was August 15th, 1930? *$$ \begin{align} d &\equiv f\left( {\left\lfloor \frac{1930}{100}\right\rfloor} \right)+g(\text{mod}\left(Y,100\right))+\cancelto{ \cancelto{ 0 }{ 7 } }{ 15-8 }~\left(\text{mod }7\right) \\ &= \cancelto{ \cancelto{ 5 }{ 12 } }{ 3+9 }+0 \\ &= 5\rightarrow \text{Friday} \end{align}

Tools

Additional Notes

Dooms Days

These are dates that all share the same day throughout the year

  • 1/3 (1/4 leap year)
  • 2/7 (2/1 leap year)
  • 3/14
  • 4/4
  • 5/9
  • 6/6
  • 7/11
  • 8/8
  • 9/5
  • 10/10
  • 11/7
  • 12/12

Dooms Days for Years

Centuries

Centuries repeat in the following cycle

  • 1700 0
  • 1800 5
  • 1900 3
  • 2000 2

Common Years

  • 2001 3
  • 2002 4
  • 2003 5
  • 2004 0
  • 2005 1
  • 2006 2
  • 2007 3
  • 2008 5
  • 2009 6
  • 2010 0
  • 2011 1
  • 2012 3
  • 2023 2

Conway’s Method for Years

  • 0 0
  • 12 1
  • 24 2
  • 36 3
  • 48 4
  • 60 5
  • 72 6
  • 84 7
  • 96 8