U(x)={−U0,0,−a≤x≤a∣x∣>a
Bounded: U0<E<0
ψ(x)=⎩⎨⎧Aekx,Csin(lx)+Dcos(lx),Be−kx,x≤a∣x∣≤ax≥a
- For even solutions, A=B and C=0
- For odd solutions, A=−B and D=0
- k=ℏ−2mE
- l=ℏ2m(E+U0)
tanz=(zz0)2−1
- Even solutions to finite square well
- z=la
- z0=ℏ2mU0a
- As z0→∞ (U0∨a→∞, so deep wide well), the number of energy states →∞
- As z0→0, the number of energy states →1
- Desmos Demo
−cotz=(zz0)2−1
- Odd solutions to finite square well
En=8ma2n2π2ℏ2−U0
Scattering: E>0
ψ(x)=⎩⎨⎧Aeikx+Be−ikx,Csin(lx)+Dcos(lx),Feikx+G−ikx,x<−a∣x∣<ax>a
- k=ℏ2mE
- l=ℏ2m(E+U0)
- For wave traveling rightward:
- G=0
- T=∣A∣2∣F∣2=[1+4E(E+U0)U02sin2(ℏ2a2m(E+U0))]−1
- T here is the transmission coefficient
- When E=8ma2n2π2ℏ2−U0, T=1. I.e., when the energy matches that of an infinite square well, transmission probability is 100%