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Helmholtz Theorem
Helmholtz Theorem
Feb 09, 2025
1 min read
Physics
∇
⋅
F
=
D
∧
∇
×
F
=
C
→
F
=
−
∇
U
+
∇
×
W
U
=
4
π
1
∫
∣
r
−
r
′
∣
D
(
r
′
)
d
3
r
′
Graph View
Table of Contents
∇
⋅
F
⃗
=
D
∧
∇
×
F
⃗
=
C
⃗
→
F
=
−
∇
U
+
∇
×
W
⃗
\displaystyle \nabla \cdot \vec{F}=D\land \nabla \times \vec{F}=\vec{C}\rightarrow F=-\nabla U+\nabla \times \vec{W}
∇
⋅
F
=
D
∧
∇
×
F
=
C
→
F
=
−
∇
U
+
∇
×
W
U
=
1
4
π
∫
D
(
r
⃗
′
)
∣
r
⃗
−
r
⃗
′
∣
d
3
r
′
\displaystyle U=\frac{1}{4\pi}\int \frac{D(\vec{r}')}{\lvert \vec{r}-\vec{r}'\rvert} \, \mathrm{d}^{3}r'
U
=
4
π
1
∫
∣
r
−
r
′
∣
D
(
r
′
)
d
3
r
′
Backlinks
Fundamental Theorems of Vector Calculus