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Lorenz Gauge

Lorenz Gauge

Feb 09, 20251 min read

  • Physics

Topics

  • Canonical Momentum

∇⋅A=−μ0​ε0​∂t​V

  • Choosing this gauge makes it easier to solve for A

□2V=−ε0​1​ρ

  • □ is the d’Alembert operator

□2A=−μ0​J


Graph View

  • Topics
  • ∇⋅A⃗=−μ0ε0∂tV\displaystyle \nabla \cdot \vec{A}=-{\mu}_{0}{\varepsilon}_{0}\partial_{t}V∇⋅A=−μ0​ε0​∂t​V
  • □2V=−1ε0ρ\displaystyle \Box ^{2}V=-\frac{1}{{\varepsilon}_{0}}\rho□2V=−ε0​1​ρ
  • □2A⃗=−μ0J⃗\displaystyle \Box ^{2}\vec{A}=-{\mu}_{0}\vec{J}□2A=−μ0​J

Backlinks

  • Gauge Theory

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