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Relativistic Energy
Relativistic Energy
Jan 27, 2024
1 min read
Physics
E
=
K
+
m
c
2
=
γm
c
2
K
is the
relativistic kinetic energy
E
2
=
(
m
c
2
)
2
+
(
p
c
)
2
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Table of Contents
E
=
K
+
m
c
2
=
γ
m
c
2
E=K+mc^2=\gamma mc^2
E
=
K
+
m
c
2
=
γm
c
2
E
2
=
(
m
c
2
)
2
+
(
p
c
)
2
E^2=(mc^2)^2+(pc)^2
E
2
=
(
m
c
2
)
2
+
(
p
c
)
2
Backlinks
Einstein's Postulates
Relativistic Quantities