AM-GM Inequality

#Math

$\displaystyle \frac{a_{1}+\ldots+a_{n}}{n}\geq\sqrt[n]{ a_{1}\ldots a_{n} }$

• The arithmetic mean of a list of positive numbers is greater than or equal to those numbers' geometric mean

$\displaystyle a^{2}+b^{2}\geq 2ab~\forall~a,b\geq0$