Atomic Polarizability

#Physics
Atomic Polarizabilities $\displaystyle \left(\frac{\alpha}{4\pi {\varepsilon}_{0}}\right)$ in units of $\displaystyle 10^{-30}\mathrm{m^{3}}$

$\displaystyle \ce{H}$$\displaystyle \ce{He}$$\displaystyle \ce{Li}$$\displaystyle \ce{Be}$$\displaystyle \ce{C}$$\displaystyle \ce{Ne}$$\displaystyle \ce{}$ $\displaystyle \ce{Na}$$\displaystyle \ce{Ar}$$\displaystyle \ce{K}$$\displaystyle \ce{Cs}$
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