Bohr Radius

#Physics

$\displaystyle a_{0}=\frac{4\pi {\varepsilon}{0}\hbar ^{2}}{m{e}e^{2}}\approx 0.529 \overset{\lower.5em\circ}{\mathrm{A}}$

• $\displaystyle \overset{\lower.5em\circ}{\mathrm{A}}$ is the Angstrom