Constant Velocity Lienard-Wiechert Potentials

#Physics

$\displaystyle \vec{E}(\vec{r},t)=kq \frac{1-v^{2} /c^{2}}{(1-v^{2} \sin ^{2}\theta /c^{2})^{3 /2}} \frac{\vec{R}}{R^{2}}$

• $\displaystyle \vec{R}\equiv \vec{r}-\vec{v}t$
  

$\displaystyle \vec{B}=\frac{1}{c}(\mathscr{\hat{r}}\times \vec{E})=\frac{1}{c^{2}}(\vec{v}\times \vec{E})$