Continuity Equation

#Physics

$\displaystyle Q=Av$

  • $\displaystyle Q$ is volumetric flow rate (this is conserved)
  • $\displaystyle A$ is cross sectional area of the pipe
  • $\displaystyle v$ is the linear flow velocity

$\displaystyle \frac{ \partial \rho }{ \partial t }+\nabla\cdot j=\sigma$

  • Fluid mechanics version
  • $\displaystyle \rho$ is the fluid density
  • $\displaystyle j$ is the flux of the fluid
  • $\displaystyle \sigma$ is the amount of fluid generated

$\displaystyle \frac{\partial \rho }{\partial t}+\nabla \cdot \vec{J}=0$

  • Electromagnetism version
  • $\displaystyle J$ is the current (e.g. $\displaystyle \frac{\mathrm{d}Q }{ \mathrm{d}t}$) of a quantity
  • $\displaystyle \rho$ is the quantity density (e..g charge density) per unit volume
  • Can be interpreted as saying that the time rate of change in a quantity is equal to the negative of the amount leaving it
  • Can be derived by divergence theorem
  • Can also be derived by taking the divergence of Ampere's law and applying Gauss's law to $\displaystyle \nabla \cdot \vec{E}$

$\displaystyle \frac{\partial u }{\partial t}+\nabla \cdot \vec{S}=0$

$\displaystyle \frac{\partial \vec{g} }{\partial t}+\nabla \cdot \stackrel{\Rightarrow}{T}=0$

$\displaystyle \frac{ \partial P }{ \partial t }+\nabla\cdot J=0$

  • Quantum mechanics version
  • $\displaystyle P$ is the probability density function of a particle
  • $\displaystyle J$ is the probability current, or how much of a particle is flowing