Electric Field Of Ring

#Physics

$E_\text{ring}=k\frac{2\pi\lambda Rz}{(z^2+R^2)^{3/2}}=\frac{Qz}{(z^2+R^2)^{3/2}}$

• $R$ is the radius of the ring
• $z$ is the distance from the center of the ring to the point