Lowering Operator

#Physics

$\displaystyle \hat{a}{-}=i \frac{\hat{p}}{p{0}}+ \frac{\hat{x}}{x_{0}}=\frac{1}{\sqrt{ 2m\hbar \omega }}\left( \hbar \frac{ \mathrm{d} }{ \mathrm{d}x }+m\omega x \right)$

$\displaystyle \hat{H}(\hat{a}{-}\Psi{n})=E_{n}-\hbar \omega$

  • Each application of $\displaystyle \hat{a}_{-}$ decreases the energy by $\displaystyle \hbar \omega$

$\displaystyle \hat{a}{-}\psi{n}=\sqrt{ n }\psi_{n-1}$

$\displaystyle \hat{a}{-}\psi{0}=0$