Radiation Field
#Physics
Topics
$\displaystyle \vec{E}{\text{rad}}(r,t)=-\frac{q}{4\pi {\varepsilon}{0}c^{2}} \frac{1}{r}\vec{a}_{\perp}(t-r/c)$
- Describes the radiated electric field due to an charge $\displaystyle q$ accelerating perpendicularly ($\displaystyle \vec{a}_{\perp}$) to the position of measurement a distance $\displaystyle r$ away as a function of time
- From 3b1b video