n→∞limk=1∑nf(a+nb−ak)⋅(nb−a)=n→∞limi=1∑nf(xi∗)Δx=∫abf(x)dx The basic idea is to add a bunch of small-width rectangles with a height of f(a+kΔx) and width of Δx nb−a is the same as Δx seen in many textbooks f(xi∗) the height of the rectangle as determined by some point xi∗ within the width of rectangle i