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Helmholtz Theorem

Helmholtz Theorem

Feb 09, 20251 min read

  • Physics

∇⋅F=D∧∇×F=C→F=−∇U+∇×W

U=4π1​∫∣r−r′∣D(r′)​d3r′


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  • ∇⋅F⃗=D∧∇×F⃗=C⃗→F=−∇U+∇×W⃗\displaystyle \nabla \cdot \vec{F}=D\land \nabla \times \vec{F}=\vec{C}\rightarrow F=-\nabla U+\nabla \times \vec{W}∇⋅F=D∧∇×F=C→F=−∇U+∇×W
  • U=14π∫D(r⃗′)∣r⃗−r⃗′∣ d3r′\displaystyle U=\frac{1}{4\pi}\int \frac{D(\vec{r}')}{\lvert \vec{r}-\vec{r}'\rvert} \, \mathrm{d}^{3}r'U=4π1​∫∣r−r′∣D(r′)​d3r′

Backlinks

  • Fundamental Theorems of Vector Calculus

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