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Feb 09, 20251 min read

$∥ x ∥_{p} = (i \sum ∣ x_{i} ∣^{p})^{\frac{1}{p}}$

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$\displaystyle \lVert \vec{x}\rVert_{p}=\left( \sum_{i}\lvert x_{i}\rvert^{p} \right)^{\frac{1}{p}}$
$\displaystyle \lVert \vec{x}\rVert_{\infty}=\text{max}_{i}(\lvert x_{i}\rvert)$