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Oct 06, 20231 min read

$ℏ = \frac{h}{2 π} = 1.054571817 \cdot 1 0^{- 34} J \cdot s$

$\displaystyle \hbar=\frac{h}{2\pi}=1.054571817\cdot10^{-34}\mathrm{ \,J\cdot s}$
$\displaystyle \hbar=4.135\cdot 10^{-15}\mathrm{\,eV\cdot s}$